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Proof step 1 from proof undel-05 (conclusion)

⊦ ¬ a ∈ s ∧ ¬ a ∈ s0 → (s -- a) ∪ (s0 -- a) = s ∪ s0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: del-in: ⊦ ¬ a ∈ s → s -- a = s;