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Proof step 1 from proof union-subset (conclusion)

⊦ s ⊆ s0 → s ∪ s1 ⊆ s0 ∪ s1

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: una: ⊦ (s ∪ s0) ∪ s1 = s ∪ s0 ∪ s1;%unc: ⊦ s ∪ s0 = s0 ∪ s;%union-subset-01: ⊦ ¬ s ∪ s1 ⊆ s0 ∪ s1 → ¬ s ⊆ s0;