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Proof step 15 from proof unsub-union-01 (
previous step
)
a ∈ s2, a1 ∈ s2, a0 ∈ s2, a ∈ s1 ∨ a ∈ s2 → a ∈ s, ∀ a. a ∈ s1 ∨ a ∈ s2 → a ∈ s ⊦ a ∈ s1, a0 ∈ s
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 16
:
a ∈ s2, a1 ∈ s2, a0 ∈ s2, a ∈ s, ∀ a. a ∈ s1 ∨ a ∈ s2 → a ∈ s ⊦ a ∈ s1, a0 ∈ s
Rule argument
Additional information