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Proof step 18 from proof unsub-union-01 (previous step)

∀ a. a ∈ s1 ∨ a ∈ s2 → a ∈ s ⊦ a ∈ s2, (a ∈ s1 → a ∈ s) ∧ (a0 ∈ s2 → a0 ∈ s)

Heuristic quantifier closing applied rule all left

And obtained the following new goals

Proof step 19:
a ∈ s1 ∨ a ∈ s2 → a ∈ s, ∀ a. a ∈ s1 ∨ a ∈ s2 → a ∈ s ⊦ a ∈ s2, (a ∈ s1 → a ∈ s) ∧ (a0 ∈ s2 → a0 ∈ s)

Rule argument

pos: left 1 terms: a

Additional information

Used terms: a