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Proof step 8 from proof rem-write-other (previous step)

a ∈ s ⊦ s = ∅, # s = 0, a0 ∈ s, (a0 ∈ st → a0 ∈ st[a, d]) ∧ st[a, d][a0] = st[a0]

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 9:
a ∈ s ⊦ a0 = a, s = ∅, # s = 0, a0 ∈ s, (a0 ∈ st → a0 ∈ st[a, d]) ∧ st[a, d][a0] = st[a0]

Rule argument

fma: a0 = a

Additional information

Used formulas: a0 = a