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Proof step 9 from proof rem-write-other (previous step)

a ∈ s ⊦ a0 = a, s = ∅, # s = 0, a0 ∈ s, (a0 ∈ st → a0 ∈ st[a, d]) ∧ st[a, d][a0] = st[a0]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
a ∈ s ⊦ s = ∅, # s = 0, a0 ∈ s, (a0 ∈ st → a0 ∈ st[a, d]) ∧ st[a, d][a0] = st[a0]

Rule argument

Additional information