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Proof step 6 from proof size-in (previous step)

a ∈ (st -- a)[a, st[a]] ⊦ # (st -- a)[a, st[a]][a, d] = # (st -- a)[a, st[a]]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
a ∈ (st -- a)[a, st[a]] ⊦ # (st -- a)[a, d] = # (st -- a)[a, st[a]]

Rule argument

Additional information

Used simplifier rules: insins: ⊦ st[a, d0][a, d] = st[a, d];