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Proof step 7 from proof size-in (previous step)

a ∈ (st -- a)[a, st[a]] ⊦ # (st -- a)[a, d] = # (st -- a)[a, st[a]]

Heuristic weak cut applied rule cut formula

And closed the goal!

Rule argument

fma: a ∈ st -- a

Additional information

Used simplifier rules: Del-in: ⊦ a ∈ st -- b ↔ a ≠ b ∧ a ∈ st;%Size-insert: ⊦ ¬ a ∈ st → # st[a, d] = # st + 1;%eq-01: ⊦ m + n = m + n0 ↔ n = n0; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2 Used formulas: a ∈ st -- a