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Proof step 4 from proof size (previous step)

st = (st -- a)[a, st[a]] ⊦ #(st -- a) = # st - 1

User applied rule insert equation

And obtained the following new goals

Proof step 5:
⊦ #((st -- a)[a, st[a]] -- a) = # (st -- a)[a, st[a]] - 1

Rule argument

pos: left 1 flags: discard

Additional information