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Proof step 5 from proof size (previous step)

⊦ #((st -- a)[a, st[a]] -- a) = # (st -- a)[a, st[a]] - 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
⊦ #(st -- a) = # (st -- a)[a, st[a]] - 1

Rule argument

Additional information

Used simplifier rules: insert: ⊦ st[a, d] -- a = st -- a;%deldel: ⊦ st -- a -- a = st -- a;