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Proof step 15 from proof subset-size (previous step)

st1[a] = d ∧ a ∈ st1, # st0 < # st1, a ∈ st1, st1 ⊆ st0, ∀ st0. # st0 < # st1 → ¬ st1 ⊆ st0 ⊦ st1 = ∅, st1 = ∅

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information