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Proof step 16 from proof subset-size (previous step)

# st0 < # st1, a ∈ st1, st1 ⊆ st0, ∀ st0. # st0 < # st1 → ¬ st1 ⊆ st0 ⊦ st1 = ∅

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: st0

Additional information

Used terms: st0