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Proof step 4 from proof elim-fromto (previous step)

⌜x⌝ = σ0 + σ1, # σ0 = ⌜n⌝ , n ≤ # x ⊦ σ0 = ⌜x to n⌝ ∧ σ1 = ⌜x from n⌝

User applied rule constructor cut

And obtained the following new goals

Proof step 5:
σ0 = ⌜x0⌝ , ⌜x⌝ = σ0 + σ1, # σ0 = ⌜n⌝ , n ≤ # x ⊦ σ0 = ⌜x to n⌝ ∧ σ1 = ⌜x from n⌝

Rule argument

var: σ0

Additional information

Used simplifier rules: append-inf: ⊦ ⌜nf⌝ + σ = ⌜nf⌝ ;%append-assoc: ⊦ (σ + σ1) + σ2 = σ + σ1 + σ2;%stream freely generated by ⌜ ⌝, ⌜ ⌝;;%disj: ⊦ ⌜x⌝ ≠ ⌜nf⌝ ; from specification stream-basic