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Proof step 5 from proof elim-fromto (previous step)

σ0 = ⌜x0⌝ , ⌜x⌝ = σ0 + σ1, # σ0 = ⌜n⌝ , n ≤ # x ⊦ σ0 = ⌜x to n⌝ ∧ σ1 = ⌜x from n⌝

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
⌜x⌝ = ⌜x0⌝ + σ1, # x0 ≤ # x ⊦ x0 = x to # x0 ∧ σ1 = ⌜x from # x0⌝

Rule argument

Additional information

Used simplifier rules: size-fin: ⊦ # ⌜x⌝ = ⌜# x⌝ ;%inj-02: ⊦ ⌜x⌝ = ⌜x0⌝ ↔ x = x0; from specification stream-basic%inj: ⊦ ⌜m⌝ = ⌜m0⌝ ↔ m = m0; from specification nat-inf-basic