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Proof step 2 from proof leq-symm-2 (previous step)

σ1 ≤ σ2, σ2 ≤ σ1 ⊦ σ1 = σ2

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ σ1 ≤ σ2 ↔ (∃ σ. σ1 + σ = σ2)
Proof step 4:
∃ σ. σ1 + σ = σ2, σ2 ≤ σ1 ⊦ σ1 = σ2

Rule argument

spec: stream inst: name: prefix-def seq: ⊦ σ1 ≤ σ2 ↔ (∃ σ. σ1 + σ = σ2) subst: [σ2, σ1] → [σ2, σ1] flags: rewrite, current

Additional information

Used terms: σ2, σ1