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Proof step 4 from proof leq-symm-2 (previous step)

∃ σ. σ1 + σ = σ2, σ2 ≤ σ1 ⊦ σ1 = σ2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
σ1 + σ ≤ σ1 ⊦ σ = [], # σ1 = ∞

Rule argument

Additional information

Used simplifier rules: appendend-equal: ⊦ σ + σ0 = σ ↔ ¬ ¬(σ0 = [] ∨ # σ = ∞);%append-assoc: ⊦ (σ + σ1) + σ2 = σ + σ1 + σ2;