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Proof step 10 from proof leq-trans (previous step)

⊦ ∃ σ3. σ + σ3 = (σ + σ0) + σ1

User applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: σ0 + σ1 abort: F discard: T computed: F

Additional information

Used simplifier rules: append-assoc: ⊦ (σ + σ1) + σ2 = σ + σ1 + σ2; Used terms: σ0 + σ1