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Proof step 9 from proof leq-trans (
previous step
)
∃ σ3. (σ + σ0) + σ3 = σ2 ⊦ ∃ σ0. σ + σ0 = σ2
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 10
:
⊦ ∃ σ3. σ + σ3 = (σ + σ0) + σ1
Rule argument
Additional information