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Proof step 10 from proof eq-leninv (previous step)

nσ[n] = 0, # nσ = ∞, stutf(nσ), ∀ m. n < m → nσ[m] = 0 ⊦ # nσ = # ⌜λ n. 0⌝ ∧ (∀ n. ⌜n⌝ < # nσ → nσ[n] = ⌜λ n. 0⌝ [n])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
# nσ = ∞, nσ[n] = 0, stutf(nσ), ∀ m. n < m → nσ[m] = 0 ⊦ nσ[n0] = 0

Rule argument

Additional information

Used simplifier rules: less-inf2: ⊦ ⌜m⌝ < ∞; from specification nat-inf%sel-inf: ⊦ ⌜nnf⌝ [n] = nnf(n); from specification stream[natstream]%size-inf: ⊦ # ⌜nnf⌝ = ∞; from specification stream[natstream]