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Proof step 11 from proof eq-leninv (previous step)

# nσ = ∞, nσ[n] = 0, stutf(nσ), ∀ m. n < m → nσ[m] = 0 ⊦ nσ[n0] = 0

User applied rule all left

And obtained the following new goals

Proof step 12:
# nσ = ∞, nσ[n] = 0, stutf(nσ), n < n0 → nσ[n0] = 0 ⊦ nσ[n0] = 0

Rule argument

pos: left 4 terms: n0 abort: F discard: T computed: T

Additional information

Used terms: n0