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Proof step 12 from proof eq-leninv (previous step)

# nσ = ∞, nσ[n] = 0, stutf(nσ), n < n0 → nσ[n0] = 0 ⊦ nσ[n0] = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
# nσ = ∞, nσ[n] = 0, stutf(nσ), n0 ≤ n ⊦ nσ[n0] = 0

Rule argument

Additional information

Used simplifier rules: lels: ⊦ ¬ m < n ↔ n ≤ m; from specification nat