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Proof step 40 from proof eq-leninv (previous step)

# nσ = ⌜n0⌝ , nσ[n0 - 1] + 1 = nσ[n], ⌜n⌝ < # nσ, stutf(nσ) ⊦ # nσ = ∞

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 41:
nσ[n0 - 1] + 1 = nσ[n], # nσ = ⌜n0⌝ , stutf(nσ), n < n0 ⊦ n0 = 0

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%less-fin: ⊦ ⌜m⌝ < ⌜n⌝ ↔ m < n; from specification nat-inf%disj: ⊦ ⌜m⌝ ≠ ∞; from specification nat-inf-basic