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Proof step 41 from proof eq-leninv (previous step)

nσ[n0 - 1] + 1 = nσ[n], # nσ = ⌜n0⌝ , stutf(nσ), n < n0 ⊦ n0 = 0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 42:
n0 = m + 1, nσ[m] + 1 = nσ[n], # nσ = ⌜n0⌝ , stutf(nσ), n < n0 ⊦ n0 = 0

Rule argument

spec: nat inst: name: elim-pred-c seq: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1 subst: [n, m] → [n0, m] flags:

Additional information

Used simplifier rules: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1; (elim) Used terms: n0, m