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Proof step 63 from proof inv-get-inverse-succ (previous step)

stutf(nσ), ⌜max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n).n⌝ + ⌜1⌝ < # nσ, n ≤ n1, (# nσ = ∞ ⊃ nσ[m] = n1 ∧ (∀ m0. m < m0 → nσ[m0] = nσ[m] + 1);nσ[(# nσ).n - 1] = n1) ⊦ nσ[max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n).n + 1] = n + 1

User applied rule case distinction

And obtained the following new goals

Proof step 64:
# nσ = ∞, nσ[m] = n1 ∧ (∀ m0. m < m0 → nσ[m0] = nσ[m] + 1), stutf(nσ), ⌜max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n).n⌝ + ⌜1⌝ < # nσ, n ≤ n1 ⊦ nσ[max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n).n + 1] = n + 1
Proof step 90:
# nσ ≠ ∞, nσ[(# nσ).n - 1] = n1, stutf(nσ), ⌜max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n).n⌝ + ⌜1⌝ < # nσ, n ≤ n1 ⊦ nσ[max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n).n + 1] = n + 1

Rule argument

pos: left 4

Proof step 63 from proof inv-get-inverse-succ (previous step)

User applied rule case distinction

And obtained the following new goals

Rule argument

Additional information