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Proof step 90 from proof inv-get-inverse-succ (previous step)

# nσ ≠ ∞, nσ[(# nσ).n - 1] = n1, stutf(nσ), ⌜max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n).n⌝ + ⌜1⌝ < # nσ, n ≤ n1 ⊦ nσ[max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n).n + 1] = n + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 91:
stutf(nσ), ⌜max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n).n⌝ + ⌜1⌝ < # nσ, n ≤ nσ[(# nσ).n - 1] ⊦ nσ[max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n).n + 1] = n + 1, # nσ = ∞

Proof step 90 from proof inv-get-inverse-succ (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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