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Proof step 88 from proof inv-get-inverse-succ (previous step)

nσ[0] = 0, nσ[m + 1] = nσ[m] + 1, # nσ = ∞, nσ[n1] ≤ nσ[m], ∀ m. nσ[m] = nσ[n1] → ¬ n1 < m, nσ[n1 + 1] = nσ[n1] ∨ nσ[n1 + 1] = nσ[n1] + 1 ⊦ nσ = [], nσ[n1 + 1] = nσ[n1] + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 89:
nσ[n1 + 1] = nσ[n1], # nσ = ∞, nσ[m + 1] = nσ[m] + 1, nσ[0] = 0, nσ[n1] ≤ nσ[m], ∀ m. nσ[m] = nσ[n1] → ¬ n1 < m ⊦ nσ = []

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%eq: ⊦ m = m + n ↔ n = 0; from specification nat-basic2