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Proof step 89 from proof inv-get-inverse-succ (previous step)

nσ[n1 + 1] = nσ[n1], # nσ = ∞, nσ[m + 1] = nσ[m] + 1, nσ[0] = 0, nσ[n1] ≤ nσ[m], ∀ m. nσ[m] = nσ[n1] → ¬ n1 < m ⊦ nσ = []

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 6 terms: n1 + 1

Additional information

Used simplifier rules: s: ⊦ m < n + 1 ↔ ¬ n < m; from specification nat-basic2%ref-1: ⊦ ¬ n < n; from specification nat-basic1%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2 Used terms: n1 + 1