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Proof step 52 from proof inv-get-inverse (previous step)

stutf(nσ), max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n) = ∞, (# nσ = ∞ ⊃ ∃ m. nσ[m] = n1 ∧ (∀ m0. m < m0 → nσ[m0] = n1 + 1);nσ[(# nσ).n - 1] = n1), stutf(nσ), n ≤ n1 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 53:
max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n) = ∞, stutf(nσ), n ≤ n1, (# nσ = ∞ ⊃ nσ[m] = n1 ∧ (∀ m0. m < m0 → nσ[m0] = nσ[m] + 1);nσ[(# nσ).n - 1] = n1) ⊦

Proof step 52 from proof inv-get-inverse (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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