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Proof step 53 from proof inv-get-inverse (previous step)

max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n) = ∞, stutf(nσ), n ≤ n1, (# nσ = ∞ ⊃ nσ[m] = n1 ∧ (∀ m0. m < m0 → nσ[m0] = nσ[m] + 1);nσ[(# nσ).n - 1] = n1) ⊦

User applied rule case distinction

And obtained the following new goals

Proof step 54:
# nσ = ∞, nσ[m] = n1 ∧ (∀ m0. m < m0 → nσ[m0] = nσ[m] + 1), max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n) = ∞, stutf(nσ), n ≤ n1 ⊦
Proof step 65:
# nσ ≠ ∞, nσ[(# nσ).n - 1] = n1, max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n) = ∞, stutf(nσ), n ≤ n1 ⊦

Rule argument

pos: left 4

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