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Proof step 14 from proof leninv-inf-strong (previous step)

# nσ = ∞, nσ[m] = m0 + 1, stutf(nσ), ∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0] ⊦ ∃ m. m0 + 1 < nσ[m]

User applied rule all left

And obtained the following new goals

Proof step 15:
# nσ = ∞, nσ[m] = m0 + 1, stutf(nσ), ∃ m0. m < m0 ∧ nσ[m] < nσ[m0] ⊦ ∃ m. m0 + 1 < nσ[m]

Rule argument

pos: left 4 terms: m abort: F discard: T computed: F

Additional information

Used terms: m