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Proof step 15 from proof leninv-inf-strong (previous step)

# nσ = ∞, nσ[m] = m0 + 1, stutf(nσ), ∃ m0. m < m0 ∧ nσ[m] < nσ[m0] ⊦ ∃ m. m0 + 1 < nσ[m]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
nσ[m] = m0 + 1, # nσ = ∞, m0 + 1 < nσ[m1], m < m1, stutf(nσ) ⊦ nσ[m1] = 0, m1 = 0, ∃ m. m0 + 1 < nσ[m]

Rule argument

Additional information

Used simplifier rules: lf-02: ⊦ m < n ∧ m = n0 → n0 < n; (forward) from specification nat-basic1%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1