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Proof step 13 from proof leninv-inf (previous step)

∀ n. ∃ n0. n < n0 ∧ (∃ m. nσ[m] = n0 - 1 ∧ ¬(∀ m0. m < m0 → nσ[m0] = n0 - 1)), # nσ = ∞, stutf(nσ) ⊦ ∃ m0. m < m0 ∧ nσ[m] < nσ[m0]

User applied rule all left

And obtained the following new goals

Proof step 14:
∃ n0. nσ[m] + 1 < n0 ∧ (∃ m. nσ[m] = n0 - 1 ∧ ¬(∀ m0. m < m0 → nσ[m0] = n0 - 1)), # nσ = ∞, stutf(nσ) ⊦ ∃ m0. m < m0 ∧ nσ[m] < nσ[m0]

Rule argument

pos: left 1 terms: nσ[m] + 1 abort: F discard: T computed: F

Additional information

Used terms: nσ[m] + 1