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Proof step 14 from proof leninv-inf (previous step)

∃ n0. nσ[m] + 1 < n0 ∧ (∃ m. nσ[m] = n0 - 1 ∧ ¬(∀ m0. m < m0 → nσ[m0] = n0 - 1)), # nσ = ∞, stutf(nσ) ⊦ ∃ m0. m < m0 ∧ nσ[m] < nσ[m0]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
# nσ = ∞, nσ[m0] = n - 1, stutf(nσ), nσ[m] + 1 < n, m0 < m1 ⊦ nσ[m1] = n - 1, ∃ m0. m < m0 ∧ nσ[m] < nσ[m0]

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; from specification nat-basic1%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1