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Proof step 56 from proof leninv-inf (previous step)

# nσ = ⌜n1⌝ + ⌜1⌝ , stutf(nσ), ∀ n. ∃ n0. n < n0 ∧ (∃ m. ¬ n1 < m ∧ nσ[m] = n0 - 1) ⊦

User applied rule all left

And obtained the following new goals

Proof step 57:
# nσ = ⌜n1⌝ + ⌜1⌝ , stutf(nσ), ∃ n0. nσ[n1] + 1 < n0 ∧ (∃ m. ¬ n1 < m ∧ nσ[m] = n0 - 1), ∀ n. ∃ n0. n < n0 ∧ (∃ m. ¬ n1 < m ∧ nσ[m] = n0 - 1) ⊦

Rule argument

pos: left 3 terms: nσ[n1] + 1 abort: F discard: F computed: F

Additional information

Used terms: nσ[n1] + 1