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Proof step 57 from proof leninv-inf (previous step)

# nσ = ⌜n1⌝ + ⌜1⌝ , stutf(nσ), ∃ n0. nσ[n1] + 1 < n0 ∧ (∃ m. ¬ n1 < m ∧ nσ[m] = n0 - 1), ∀ n. ∃ n0. n < n0 ∧ (∃ m. ¬ n1 < m ∧ nσ[m] = n0 - 1) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 58:
nσ[m] = n - 1, # nσ = ⌜n1⌝ + ⌜1⌝ , m ≤ n1, nσ[n1] + 1 < n, stutf(nσ), ∀ n. ∃ n0. n < n0 ∧ (∃ m. ¬ n1 < m ∧ nσ[m] = n0 - 1) ⊦

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; from specification nat-basic1%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%lels: ⊦ ¬ m < n ↔ n ≤ m; from specification nat