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Proof step 21 from proof leninv-zero (previous step)

stutf(nσ), ∀ m. (∃ m0. ⌜m0⌝ < # nσ ∧ nσ[m0] = m - 1) → m = 0 ⊦ ∀ n. # nσ ≠ ⌜n⌝

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 22:
# nσ = ⌜n⌝ , stutf(nσ), ∀ m. (∃ m0. m0 < n ∧ nσ[m0] = m - 1) → m = 0 ⊦

Rule argument

Additional information

Used simplifier rules: less-fin: ⊦ ⌜m⌝ < ⌜n⌝ ↔ m < n; from specification nat-inf