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Proof step 22 from proof leninv-zero (previous step)

# nσ = ⌜n⌝ , stutf(nσ), ∀ m. (∃ m0. m0 < n ∧ nσ[m0] = m - 1) → m = 0 ⊦

User applied rule constructor cut

And obtained the following new goals

Proof step 23:
n = n0 +1, # nσ = ⌜n⌝ , stutf(nσ), ∀ m. (∃ m0. m0 < n ∧ nσ[m0] = m - 1) → m = 0 ⊦

Rule argument

var: n

Additional information

Used simplifier rules: stutf-nonempty: ⊦ stutf(nσ) → (¬ nσ ≠ [] ↔ false);%nat freely generated by 0, +1;;%size-empty-equiv: ⊦ # nσ = ⌜0⌝ ↔ nσ = []; from specification stream[natstream]