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Proof step 5 from proof leq-leninv (previous step)

leninv(nσ) = ⌜n0⌝ , ⌜n⌝ < # nσ, stutf(nσ), n0 < nσ[n] ⊦ nσ[n] = 0

User applied rule constructor cut

And obtained the following new goals

Proof step 6:
n0 = 0, leninv(nσ) = ⌜n0⌝ , ⌜n⌝ < # nσ, stutf(nσ), n0 < nσ[n] ⊦ nσ[n] = 0
Proof step 9:
n0 = n1 +1, leninv(nσ) = ⌜n0⌝ , ⌜n⌝ < # nσ, stutf(nσ), n0 < nσ[n] ⊦ nσ[n] = 0

Rule argument

var: n0

Additional information

Used simplifier rules: nat freely generated by 0, +1;;