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Proof step 9 from proof leq-leninv (previous step)

n0 = n1 +1, leninv(nσ) = ⌜n0⌝ , ⌜n⌝ < # nσ, stutf(nσ), n0 < nσ[n] ⊦ nσ[n] = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
leninv(nσ) = ⌜n1⌝ + ⌜1⌝ , ⌜n⌝ < # nσ, stutf(nσ), n1 + 1 < nσ[n] ⊦ nσ[n] = 0

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%add-fin: ⊦ ⌜m + n⌝ = ⌜m⌝ + ⌜n⌝ ; from specification nat-inf%succ: ⊦ m +1 = m + 1; from specification nat-basic2