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Proof step 14 from proof less-leninv (previous step)

nσ[n + 1] = nσ[n] + 1, # nσ = ∞, stutf(nσ), nσ[m] < nσ[n], ∀ m1. m < m1 → nσ[m1] = nσ[m] + 1 ⊦

User applied rule all left

And obtained the following new goals

Proof step 15:
nσ[n + 1] = nσ[n] + 1, # nσ = ∞, stutf(nσ), nσ[m] < nσ[n], m < n → nσ[n] = nσ[m] + 1, ∀ m1. m < m1 → nσ[m1] = nσ[m] + 1 ⊦

Rule argument

pos: left 5 terms: n abort: F discard: F computed: F

Additional information

Used terms: n