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Proof step 15 from proof less-leninv (previous step)

nσ[n + 1] = nσ[n] + 1, # nσ = ∞, stutf(nσ), nσ[m] < nσ[n], m < n → nσ[n] = nσ[m] + 1, ∀ m1. m < m1 → nσ[m1] = nσ[m] + 1 ⊦

User applied rule insert lemma

And obtained the following new goals

Proof step 16:
⊦ mon≤(nσ) ∧ m ≤ n ∧ ⌜n⌝ < # nσ → nσ[m] ≤ nσ[n]
Proof step 17:
mon≤(nσ) ∧ n ≤ m ∧ ⌜m⌝ < # nσ → nσ[n] ≤ nσ[m], nσ[n + 1] = nσ[n] + 1, # nσ = ∞, stutf(nσ), nσ[m] < nσ[n], m < n → nσ[n] = nσ[m] + 1, ∀ m1. m < m1 → nσ[m1] = nσ[m] + 1 ⊦

Rule argument

spec: inst: name: monle-leq seq: ⊦ mon≤(nσ) ∧ m ≤ n ∧ ⌜n⌝ < # nσ → nσ[m] ≤ nσ[n] subst: [nσ, m, n] → [nσ, n, m] flags: current, []

Additional information

Used terms: nσ, n, m