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Proof step 17 from proof less-leninv (previous step)

mon≤(nσ) ∧ n ≤ m ∧ ⌜m⌝ < # nσ → nσ[n] ≤ nσ[m], nσ[n + 1] = nσ[n] + 1, # nσ = ∞, stutf(nσ), nσ[m] < nσ[n], m < n → nσ[n] = nσ[m] + 1, ∀ m1. m < m1 → nσ[m1] = nσ[m] + 1 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: stutf-monle: ⊦ stutf(nσ) → (¬ mon≤(nσ) ↔ false);%ref-1: ⊦ ¬ n < n; from specification nat-basic1%s: ⊦ m < n + 1 ↔ ¬ n < m; from specification nat-basic2%ler: ⊦ m ≤ m; from specification nat%f: ⊦ m < n → n ≠ 0; from specification nat-basic1%lf-01: ⊦ m < n ∧ n = n0 → m < n0; (forward) from specification nat-basic1%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%eqle-one: ⊦ m = n + 1 ∧ n < n0 → m ≤ n0; (forward) from specification nat%lels-01: ⊦ ¬ m ≤ n ↔ n < m; from specification nat%less-inf2: ⊦ ⌜m⌝ < ∞; from specification nat-inf%ls-le-simp: ⊦ m < n → (n ≤ m ↔ false); from specification nat