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Proof step 5 from proof less-leninv (previous step)

m = 0, nσ[n + 1] = nσ[n] + 1, # nσ = ∞, ⌜m⌝ = leninv(nσ), stutf(nσ), m ≤ nσ[n] ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
nσ[n + 1] = nσ[n] + 1, # nσ = ∞, ⌜0⌝ = leninv(nσ), stutf(nσ) ⊦

Rule argument

Additional information

Used simplifier rules: lez: ⊦ 0 ≤ m; from specification nat