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Proof step 6 from proof less-leninv (previous step)

nσ[n + 1] = nσ[n] + 1, # nσ = ∞, ⌜0⌝ = leninv(nσ), stutf(nσ) ⊦

User applied rule flip equation

And obtained the following new goals

Proof step 7:
nσ[n + 1] = nσ[n] + 1, # nσ = ∞, leninv(nσ) = ⌜0⌝ , stutf(nσ) ⊦

Rule argument

pos: left 3

Additional information