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Proof step 15 from proof maxinf-fin (previous step)

np(n) ∧ (∀ m. np(m) → ¬ n < m), max∞(np) = ⌜n0⌝ , np(n0), ∀ m. np(m) → ¬ n0 < m ⊦ n0 = n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information