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Proof step 16 from proof maxinf-fin (
previous step
)
max∞(np) = ⌜n0⌝ , np(n), np(n0), ∀ m. np(m) → ¬ n < m, ∀ m. np(m) → ¬ n0 < m ⊦ n0 = n
User applied rule all left
And obtained the following new goals
Proof step 17
:
max∞(np) = ⌜n0⌝ , np(n), np(n0), np(n0) → ¬ n < n0, ∀ m. np(m) → ¬ n0 < m ⊦ n0 = n
Rule argument
pos: left 4 terms: n0 abort: F discard: T computed: T
Additional information
Used terms: n0