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Proof step 36 from proof stutf-maxinf-is-fin (previous step)

# nσ = ∞, stutf(nσ), ∀ n1. ¬ n1 < n2 → nσ[n1] = nσ[n] ⊦ ∃ n1. n0 < n1 ∧ nσ[n1] = nσ[n]

User applied rule all left

And obtained the following new goals

Proof step 37:
# nσ = ∞, stutf(nσ), ¬ n2 < n2 → nσ[n2] = nσ[n], ∀ n1. ¬ n1 < n2 → nσ[n1] = nσ[n] ⊦ ∃ n1. n0 < n1 ∧ nσ[n1] = nσ[n]

Rule argument

pos: left 3 terms: n2 abort: F discard: F computed: T

Additional information

Used terms: n2