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Proof step 37 from proof stutf-maxinf-is-fin (previous step)

# nσ = ∞, stutf(nσ), ¬ n2 < n2 → nσ[n2] = nσ[n], ∀ n1. ¬ n1 < n2 → nσ[n1] = nσ[n] ⊦ ∃ n1. n0 < n1 ∧ nσ[n1] = nσ[n]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 38:
# nσ = ∞, nσ[n2] = nσ[n], stutf(nσ), ∀ n1. ¬ n1 < n2 → nσ[n1] = nσ[n] ⊦ ∃ n1. n0 < n1 ∧ nσ[n1] = nσ[n]

Rule argument

Additional information

Used simplifier rules: ref-1: ⊦ ¬ n < n; from specification nat-basic1