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Proof step 38 from proof stutf-maxinf-is-fin (previous step)

# nσ = ∞, nσ[n2] = nσ[n], stutf(nσ), ∀ n1. ¬ n1 < n2 → nσ[n1] = nσ[n] ⊦ ∃ n1. n0 < n1 ∧ nσ[n1] = nσ[n]

User applied rule exists right

And obtained the following new goals

Proof step 39:
# nσ = ∞, nσ[n2] = nσ[n], stutf(nσ), ∀ n1. ¬ n1 < n2 → nσ[n1] = nσ[n] ⊦ n0 < n2 ∧ nσ[n2] = nσ[n], ∃ n1. n0 < n1 ∧ nσ[n1] = nσ[n]

Rule argument

pos: right 1 terms: n2 abort: F discard: F computed: T

Additional information

Used terms: n2