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Proof step 2 from proof fill-fill-01 (previous step)

⊦ bits = [], fillsgn(n, fillsgn(n, bits)) = fillsgn(n, bits)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ n ≤ # bits → fillsgn(n, bits) = bits
Proof step 4:
¬ n ≤ # fillsgn(n, bits) ⊦ bits = [], fillsgn(n, fillsgn(n, bits)) = fillsgn(n, bits)

Rule argument

name: fillsgn-longer rotate: F subst: [bits, n] → [fillsgn(n, bits), n]

Additional information

Used terms: fillsgn(n, bits), n